http://www.youtube.com/watch?v=-UEG5DLMd5o
King Arthur has invited 4 knights to a party but isn’t sure where to sit them. How many different ways can you find to sit 4 knights around a table. I know how many different ways there are and the first person to post the correct number wins a prize!
Can you find a pattern?
How many ways would there be for 5 knights?
These are my infrared for king Arthur P is pinck.
1.K. P. G. R. B . O
2. K. G. P. B. R . O
3. K. P. B. R. G . O
4. K. G. R. P. B. O
5. K. B. G. R. P. O
6. K. B. R. P. G. O
7. K. B. P. G. R. O
Keep going Gabby!!!
I have fond all of the ansers and there is twenty four these are all of them
k 1 2 3 4
k p b g r
k p b r g
k p g b r
k p g r b
k p r b g
k p r g b
k g p b r
k g p r b
k g r p b
k g r b p
k g b r p
k g b p r
k b p r g
k b p g r
k b g p r
Each night had six when they were in seat 1 and 2 and 3 and 4.
1 2 3 4 5
KA O T G P
KA O P T G
KA O T G P
KA O T P G
KA O G T P
We know that there is 6 answers for each knight.
My ideas for king Athurs problam are
k 1 2 3 4 5
k stands for king
numbers at beginning meanes how many ideas we have got …
1 k 1 b r g p
2 k 2 brgp
3 k 3 g r p b
4 k 4 g r b p
k 5 r b p g
k 6 p g r b
k 7 p k g b
k 8 b r g p
k 9 p g r b
k 10 b p k g
k 11 b p g r
k 12 p g r b
k 13 b g r p
k 14 b g p r
k 15 p r g b
k 16 pr g b
k 17 b g rp
We know that each night has 6 answers .
k1 2r 3p 4b 5g
k1 2r 3p 4g 5b
k1 2r 3g 4b 5p
We know that each knight has 6 diffrent answers in seat 1.
k1 2r 3p 4b 5g
k1 2r 3p 4g 5b
k1 2r 3g 4b 5p
We know that each knight has 6 diffrent answers in seat 1.
1. k R G P B
2. k R G B P
3. K R B G P
4. k R B P G
5. k R P B G
6. k R P G B
7. K B R G P
We know that there is 6 answers for each knight.
1.K B. G. R. P.
2. K. B. G. P. R.
3. K. B. R. G. P.
4. K. B. R. P. G.
5. K. B. P. G. R.
6. K. B. P. R. G.
We know that each knight has 6 answers.
1. k R G P B
2. k R G B P
3. K R B G P
4. k R B P G
5. k R P B G
6. k R P G B
7. K B R G P
We know that there is 6 answers for each knight.
R /B/G/P/
R/B/P/G
R/P/G/B
R/G/B/P
R/P/G/B
R/P/G/B
We know that there is 6 different answers for each knight when they are sat in first.
Wow, I was so impressed with this lesson when I was in, I really liked the how resilient you all were trying to find all the possibilities. Wonder if you can get to the final solution. Well done!
1.k r b g p.
2.k r g b p.
3.k r b p g.
4.k r p b g.
5.k r p g b.
6.k r g p b.
Well done Chloe, what can you tell me from these first 6 combinations?
My ideas for Kjng Arthurs table are
BGPR
K 1234
KBGPR
KBGRP
KBRGP
KBRPG
KBPGR
KBPRG
There are 6 combinations for each knight. So there are 6X4 which is 24.
So there is 24 combinations I think.
Well done Daniel, I wonder if Mr Banham would agree with you?
Massie
These are my ideas of king Arthur ‘s problem first I am going to do it with 5 nights
o stands for orange
1 k o p g r
2 k p g r o
3 k g r o p
4 k r o p g
5 k o p g r
am I right wright with all my ideas hope I solved your problem
Mrs Paddock
A brilliant start Massie, are they the only possibilities?